Array.prototype.with()
Baseline 2023
Newly available
Since July 2023, this feature works across the latest devices and browser versions. This feature might not work in older devices or browsers.
The with()
method of Array
instances is the copying version of using the bracket notation to change the value of a given index. It returns a new array with the element at the given index replaced with the given value.
Syntax
arrayInstance.with(index, value)
Parameters
index
-
Zero-based index at which to change the array, converted to an integer.
- Negative index counts back from the end of the array — if
-array.length <= index < 0
,index + array.length
is used. - If the index after normalization is out of bounds, a
RangeError
is thrown.
- Negative index counts back from the end of the array — if
value
-
Any value to be assigned to the given index.
Return value
A new array with the element at index
replaced with value
.
Exceptions
RangeError
-
Thrown if
index >= array.length
orindex < -array.length
.
Description
The with()
method changes the value of a given index in the array, returning a new array with the element at the given index replaced with the given value. The original array is not modified. This allows you to chain array methods while doing manipulations.
By combining with()
with at()
, you can both write and read (respectively) an array using negative indices.
The with()
method never produces a sparse array. If the source array is sparse, the empty slots will be replaced with undefined
in the new array.
The with()
method is generic. It only expects the this
value to have a length
property and integer-keyed properties.
Examples
Creating a new array with a single element changed
const arr = [1, 2, 3, 4, 5];
console.log(arr.with(2, 6)); // [1, 2, 6, 4, 5]
console.log(arr); // [1, 2, 3, 4, 5]
Chaining array methods
With the with()
method, you can update a single element in an array and then apply other array methods.
const arr = [1, 2, 3, 4, 5];
console.log(arr.with(2, 6).map((x) => x ** 2)); // [1, 4, 36, 16, 25]
Using with() on sparse arrays
The with()
method always creates a dense array.
const arr = [1, , 3, 4, , 6];
console.log(arr.with(0, 2)); // [2, undefined, 3, 4, undefined, 6]
Calling with() on non-array objects
The with()
method creates and returns a new array. It reads the length
property of this
and then accesses each property whose key is a nonnegative integer less than length
. As each property of this
is accessed, the array element having an index equal to the key of the property is set to the value of the property. Finally, the array value at index
is set to value
.
const arrayLike = {
length: 3,
unrelated: "foo",
0: 5,
2: 4,
3: 3, // ignored by with() since length is 3
};
console.log(Array.prototype.with.call(arrayLike, 0, 1));
// [ 1, undefined, 4 ]
Specifications
Specification |
---|
ECMAScript Language Specification # sec-array.prototype.with |
Browser compatibility
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